Integrand size = 25, antiderivative size = 37 \[ \int \frac {\sec (c+d x) \tan (c+d x)}{a+a \sin (c+d x)} \, dx=\frac {\sec ^3(c+d x)}{3 a d}-\frac {\tan ^3(c+d x)}{3 a d} \]
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Time = 0.07 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {2918, 2686, 30, 2687} \[ \int \frac {\sec (c+d x) \tan (c+d x)}{a+a \sin (c+d x)} \, dx=\frac {\sec ^3(c+d x)}{3 a d}-\frac {\tan ^3(c+d x)}{3 a d} \]
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Rule 30
Rule 2686
Rule 2687
Rule 2918
Rubi steps \begin{align*} \text {integral}& = \frac {\int \sec ^3(c+d x) \tan (c+d x) \, dx}{a}-\frac {\int \sec ^2(c+d x) \tan ^2(c+d x) \, dx}{a} \\ & = \frac {\text {Subst}\left (\int x^2 \, dx,x,\sec (c+d x)\right )}{a d}-\frac {\text {Subst}\left (\int x^2 \, dx,x,\tan (c+d x)\right )}{a d} \\ & = \frac {\sec ^3(c+d x)}{3 a d}-\frac {\tan ^3(c+d x)}{3 a d} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(104\) vs. \(2(37)=74\).
Time = 0.44 (sec) , antiderivative size = 104, normalized size of antiderivative = 2.81 \[ \int \frac {\sec (c+d x) \tan (c+d x)}{a+a \sin (c+d x)} \, dx=\frac {-3+\cos (c+d x)+\cos (2 (c+d x))-2 \sin (c+d x)+\frac {1}{2} \sin (2 (c+d x))}{6 a d \left (-\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right ) \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right ) (1+\sin (c+d x))} \]
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Time = 0.16 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.65
method | result | size |
parallelrisch | \(\frac {-2-6 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-4 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{3 d a \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}\) | \(61\) |
risch | \(\frac {2 i \left (2 i {\mathrm e}^{i \left (d x +c \right )}+3 \,{\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{3 \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )^{3} d a}\) | \(63\) |
derivativedivides | \(\frac {-\frac {1}{2 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}+\frac {2}{3 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}-\frac {1}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}+\frac {4}{8 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+8}}{d a}\) | \(70\) |
default | \(\frac {-\frac {1}{2 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}+\frac {2}{3 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}-\frac {1}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}+\frac {4}{8 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+8}}{d a}\) | \(70\) |
norman | \(\frac {-\frac {2 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}-\frac {2}{3 a d}-\frac {4 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{3 d a}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}\) | \(73\) |
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Time = 0.25 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.27 \[ \int \frac {\sec (c+d x) \tan (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\cos \left (d x + c\right )^{2} - \sin \left (d x + c\right ) - 2}{3 \, {\left (a d \cos \left (d x + c\right ) \sin \left (d x + c\right ) + a d \cos \left (d x + c\right )\right )}} \]
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\[ \int \frac {\sec (c+d x) \tan (c+d x)}{a+a \sin (c+d x)} \, dx=\frac {\int \frac {\sin {\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )}}{\sin {\left (c + d x \right )} + 1}\, dx}{a} \]
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Leaf count of result is larger than twice the leaf count of optimal. 110 vs. \(2 (33) = 66\).
Time = 0.21 (sec) , antiderivative size = 110, normalized size of antiderivative = 2.97 \[ \int \frac {\sec (c+d x) \tan (c+d x)}{a+a \sin (c+d x)} \, dx=\frac {2 \, {\left (\frac {2 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {3 \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + 1\right )}}{3 \, {\left (a + \frac {2 \, a \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac {2 \, a \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} - \frac {a \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}}\right )} d} \]
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Time = 0.29 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.54 \[ \int \frac {\sec (c+d x) \tan (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\frac {3}{a {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1\right )}} - \frac {3 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1}{a {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )}^{3}}}{6 \, d} \]
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Time = 10.83 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.62 \[ \int \frac {\sec (c+d x) \tan (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {2\,\left (3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )+1\right )}{3\,a\,d\,\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-1\right )\,{\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )+1\right )}^3} \]
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